new drug that is used to treat leukemia Statistic assignment, homework help
1.
There is
a new drug that is used to treat leukemia. The following data represents the
remission time in weeks for a random sample of 21 patients using the drug.
10 |
7 |
32 |
23 |
22 |
6 |
16 |
11 |
20 |
19 |
6 |
17 |
35 |
6 |
10 |
34 |
32 |
25 |
13 |
9 |
6 |
Let X be a random variable representing the remission time in
weeks for all patients using the new drug. Assume that the distribution of x is
normal. A previously used drug treatment has a mean remission time of 12.5
weeks. Does the data indicate that the mean remission time using the new drug
is different from 12.5 week at a level of significance of 0.01?
State the null hypothesis:
A. µ=12.5
B. µ≠12.5
C. µ<12.5
D. µ>12.5
Answer:
Choose an item.
State the alternative hypothesis:
A. µ=12.5
B. µ≠12.5
C. µ<12.5
D. µ>12.5
Answer:
Choose an item.
Let X be a random variable representing the remission |
State
the level of significance:
A. 0.001
B. 0.01
C. 0.05
D. 0.10
Answer:
Choose an item.
Let X be a random variable representing the remission |
State
the test statistic:
A. 0.058
B. 0.552
C. 1.058
D. 2.106
Answer:
Choose an item.
Perform
calculations
Please write down your solutions or copy
and paste your Excel output here:
Then answer the following two questions:
Critical value:
A.
0.050
B.
1.960
C.
2.086
D.
2.845
Answer:
Choose an item.
P-value:
A.
p <0.001
B.
0.001 ≤ p <0.01
C.
0.01 ≤
p <0.05
D.
0.05 ≤
p
Answer:
Choose an item.
Statistical Conclusion
A. Reject the null hypothesis
B. Do not reject the null hypothesis
Answer:
Choose an item.
Experimental Conclusion
A. There
is sufficient evidence to conclude that the mean remission time using the new
drug is different from 12.5 week at a level of significance of 0.01.
B. There
is no sufficient evidence to conclude that the mean remission time using the
new drug is different from 12.5 week at a level of significance of 0.01.
Answer:
Choose an item.
2.
We
wish to test the claim that the mean body mass index (BMI) of men is equal to
the mean BMI of women. Use the data below
to test this claim.
Men |
Women |
20 |
29 |
37 |
28 |
46 |
20 |
23 |
28 |
20 |
42 |
23 |
45 |
21 |
19 |
15 |
45 |
20 |
16 |
28 |
32 |
27 |
38 |
20 |
45 |
30 |
41 |
22 |
34 |
27 |
28 |
38 |
21 |
29 |
42 |
20 |
21 |
16 |
30 |
27 |
28 |
42 |
30 |
37 |
43 |
39 |
40 |
39 |
16 |
32 |
44 |
16 |
15 |
21 |
16 |
26 |
20 |
17 |
41 |
39 |
16 |
State
the Null Hypothesis
A. μ_{1 }= μ_{2}
B. μ_{1 }≠ μ_{2}
C. μ_{1 }> μ_{2}
D. μ_{1 }< μ_{2}
Where μ_{1 }and μ_{2} are the mean body mass
index for men and women, respectively.
Answer:
Choose an item.
State the alternative hypothesis:
A. μ_{1 }= μ_{2}
B. μ_{1 }≠ μ_{2}
C. μ_{1 }> μ_{2}
D. μ_{1 }< μ_{2}
Answer:
Choose an item.
State
the Level of significance
State the level of significance:
A. 0.001
B. 0.01
C. 0.05
D. 0.10
Answer:
Choose an item.
State the test statistic (its absolute value, for example the
absolute value of -1.5 is 1.5):
A. 0.058
B. 0.515
C. 1.273
D. 2.108
Answer:
Choose an item.
Perform
calculations
Please write down your solutions or copy
and paste your Excel output here:
Then answer the following two questions:
Critical value:
A.
0.050
B.
1.960
C.
2.002
D.
2.045
Answer:
Choose an item.
P-value:
A.
p <0.001
B.
0.001 ≤ p <0.01
C.
0.01
≤ p <0.05
D.
0.05
≤ p
Answer:
Choose an item.
Statistical Conclusion
A. Reject the null hypothesis
B. Do not reject the null hypothesis
Answer:
Choose an item.
Experimental Conclusion
There is sufficient
evidence to conclude that the mean body mass index (BMI) of mean is